1樓:
private function c(n as integer, k as integer) as long
c = f(n) / f(k) / f(n - k)end function
private function f(i as integer) as long
f = 1
for j = 2 to i
f = f * j
next j
end function
private sub command1_click()dim n as integer, k as integern = 10 'n大於12會出錯的!
k = 3
print c(n, k)
end sub
2樓:匿名使用者
private function c(n as double, k as double) as double
c = f(n) / f(k) / f(n - k)end function
private function f(i as double) as double
f = 1
for j = 2 to i
f = f * j
next j
end function
private sub command1_click()dim n as double, k as doublen = 10 '這樣改會好一點
k = 3
print c(n, k)
end sub
一道VB程式設計題目,求大佬解答,一道vb程式設計題目求大佬解答!!!
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很簡單的一道求橢圓方程題
解 因為橢圓c y a x b 1 a b 0 的右頂點為a 1,0 代入點a,易得 b 1,當y c時 c 2 a 2 b 2 c 2 a 2 x 2 b 2 1 x 1 b 2c 2 a 2 所以過c的焦點且垂直長軸的弦長為2 1 b 2c 2 a 2 1帶入b 1而且a 2 c 2 b 2 容...