1樓：匿名使用者
private sub form_click()dim i as long, f as integer, pi as single
i = 1
f = 1
dopi = pi + (1 / i) * ff = -f
i = i + 2
loop while 1 / i > 0.00001msgbox 4 * pi
end sub
2樓：匿名使用者
let s=0
let e=0.00001
let i=0
let sign=-1
do while 1.0/(2*i+1)>=elet sign=-sign
let s=s+sign*1.0/(2*i+1)let i=i+1
loop
let s=s*4
print send
java編寫乙個計算圓周率π的近似值π=4*(1-1/3+1/5-1/7+1/9-1/11+....)
3樓：匿名使用者
import java.io.*;
public class pi
system.out.println(4*sum);}}終於申訴成功～～～
4樓：紅塵莫問_離經
public class mypi
system.out.println("π的近似值=" + sum * 4);}}
5樓：匿名使用者
void main()
printf("π=%f",4*sum);}
6樓：day配角
long cut = 1000000; // 切圓次數double pi = 0;
double a = 1 - 1.0 / 3;
double b = 5;
pi = a;
for (long i = 0; i < cut; i++) else
b += 2;
}system.out.println(pi * 4);
以下是頁面版的，開啟谷歌瀏覽器，在貼上到控制台按回車鍵即可。
var cut = 1000000; // 切圓次數var pi = 0;
var a = 1 - 1.0/3;
var b = 5;
pi = a;
for (var i = 0; i < cut; i++) elseb += 2;
}console.log(pi * 4);
以上準確說是切圓的**。
望採納。
7樓：匿名使用者
n < max;不應該是小於等於吧
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